Word Count : 204

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For (n = 1), the sum of the squares of the first natural number is (1^2 = 1). The given formula gives (\frac{1(1+1)(2\cdot1+1)}{6} = \frac{1\cdot2\cdot3}{6} = 1). Hence the result is true for (n ______ ____ ________ ____ ____ ___ ________ ______ _______ ___ ___ _________.
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