Suppose that there is a mixture having a specific rotation of +75^o and an enantiomeric excess of 60%. Find out the enantiomeric composition of the mixture. 

To calculate the enantiomeric composition of the mixture, we need to use the relationship between the observed specific rotation, enantiomeric excess (ee), and the specific rotation of the pure enantiomer.

The formula to calculate enantiomeric excess (ee) is:

\[
\text{ee} = \frac{[\alpha]_{\text{observed}}}{[\alpha]_{\text{pure}}} \times 100
\]

Where:
- \([\alpha]_{\text{observed}}\) is the observed specific rotation,
- \([\alpha]_{\text{pure}}\) is the specific rotation of the pure enantiomer.

Given that the observed specific rotation is +75° and the enantiomeric excess is 60%, we can calculate the ____ _________ ___ ______ ____ _________ ________ __________ _________ ______ ___ __________.
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