Is the matrix of the linear operator T non-singular? Justify your answer.
Yes. The matrix of the linear operator (T) is non-singular because (T) is invertible. Indeed, if ___ ____ __________ _________ _______ ___ _________ ______ __________ ___ ______.
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Check that f(x) is well defined and 1 - 1.
) Using the fact that for any two matrices A and B, prove the identity
Check that .
जाँच कीजिए कि किसी के लिए
है।
Check that for
and
for
.
) Which of the following statements are true and which are false? Justify your answer with a short proof or a counterexample.
i) The function defined by
is 1-1.
ii) The operation $ defined byx y = \log(xy)is a binary operation onS, whereSis the set\{x \in \mathbf{R} \mid x > 0\}$.
iii) The set is a subspace of
.
iv) There is no matrix of rank 6.
v) If V and V' are vector spaces and is a linear transformation, then whenever
are linearly independent,
are also linearly independent.
vi) If V is a vector space and is a linear operator with
, then T is not diagonalisable.
vii) The degree of the minimal polynomial of a matrix is at most 2.
viii) For any matrix A,
.
ix) The only matrix which is both symmetric and skew-symmetric is the zero matrix.
x) There is no co-ordinate transformation that transforms the quadratic form x2 + y2 + z2 to the quadratic form xz + yz.
Find the values of for which the matrix
is Hermitian.