Question
A parachutist, whose weight (actually mass) is , drops from a helicopter
above the ground. She falls towards the earth under the influence of gravity. Assume that the gravitational force is constant. Assume that the force due to air resistance is proportional to the velocity of the parachutist. The proportionality constant is
when the parachute is closed, and is
when it is open. If the parachute does not open until
after the parachutist leaves the helicopter, after how many seconds will she hit the ground?
b) A projectile is fixed with a constant speed v at two different angles of projection and
such that it gives the same range. Show that
Answer :
Word Count : 332
Let downward direction be taken as positive. The mass of the parachutist is (m=64) kg. The gravitational force is (mg=64\times 9.8=627.2) N. The resistive force is proportional to velocity and acts upward, so its magnitude is (kv). While the parachute is closed ((k_1=16) kg/s), the equation of motion is [ m\frac{dv}{dt}=mg-k_1 v. ] This is ______ ______ ____ _______ ________ __________ _________.
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Let downward direction be taken as positive. The mass of the parachutist is (m=64) kg. The gravitational force is (mg=64\times 9.8=627.2) N. The resistive force is proportional to velocity and acts upward, so its magnitude is (kv). While the parachute is closed ((k_1=16) kg/s), the equation of motion is [ m\frac{dv}{dt}=mg-k_1 v. ] This is ______ ______ ____ _______ ________ __________ _________.
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