) Consider a machine that brings all the operands to registers before performing the ALU operation. The machine uses PC, IR, and MAR registers. All memory accesses bring data to the AX register. The operations are performed in AC and AX registers, and results are stored in the AC register. List and explain all the microoperations required to execute an instruction AC AC+[MAR] on this machine
To execute the instruction `AC ← AC + [MAR]` on a machine with the specified architecture, we need to carefully orchestrate several microoperations involving various registers and memory operations. Let's break down the process step by step:
### 1. Understanding the Architecture
Given the architecture:
- Registers: PC (Program Counter), IR (Instruction Register), MAR (Memory Address Register), AC (Accumulator), AX (a temporary data register).
- Memory Access: All memory accesses bring data into the AX register.
- ALU Operation: Operations are performed between AC and AX, with results stored in the AC register.
### Instruction: `AC ← AC + [MAR]`
Objective: Add the value from memory address specified by MAR to the value in AC and store the result in AC.
### Microoperations Breakdown
To execute this instruction, the following microoperations are performed:
1. Fetch the Instruction
- MAR ← PC: Load the address of the next instruction from the PC into MAR.
- Read Memory: Fetch the instruction from the memory address specified by MAR and load it into IR.
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