Question

Write a program in 8086 assembly language, which converts a packed four-digit packed BCD number to equivalent four ASCII digits; for example, a packed BCD number “4367” stored in a word is converted to ASCII “4”, “3”, “6”, “7”. Explain the algorithm of the program.

13 Sep 2024
Answer :
Word Count : 1082

To convert a packed BCD (Binary-Coded Decimal) number to its ASCII equivalent in 8086 assembly language, we must first understand the structure of the packed BCD number and the corresponding ASCII codes for decimal digits.

In a packed BCD format, two decimal digits are stored in a single byte. Each digit takes 4 bits: the high nibble stores the first digit (0-9), and the low nibble stores the second digit (0-9). For instance, the packed BCD number 4367, represented as 0x43 and 0x67 in hexadecimal, would be stored in two bytes: 0x43 for the digits "4" and "3" and 0x67 for the digits "6" and "7".

To convert this packed BCD number into ASCII characters, each digit in the packed BCD must be extracted and then converted into its corresponding ASCII value. The ASCII values for the digits 0-9 range from 0x30 to 0x39. Thus, to convert the BCD digits to ASCII, we need to add 0x30 to the value of each BCD digit.

### Algorithm

1. Input the packed BCD number: This will be a 16-bit number where each byte holds two packed decimal digits.
2. Extract the first byte and separate the high and low nibbles: The high nibble represents the first BCD digit, and the low nibble represents the second BCD digit.
3. Convert each nibble into its ASCII equivalent: Add 0x30 to the value of the nibble to get the ASCII code.
4. Repeat the process for the second byte: Extract the high and low nibbles of the second byte and convert each to its ASCII equivalent.
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