Two collinear harmonic oscillations, each of frequency , have amp

Question

Two collinear harmonic oscillations, each of frequency $\omega_0$ , have amplitudes, a₁ and a₂ and initial phases, $\phi_1 = \frac{\pi}{3}$ and $\phi_2 = \frac{4\pi}{3}$ , respectively. Show that, when these oscillations are superposed, the amplitude of the resultant motion is equal to (a₁ - a₂). What will be the value of the resultant amplitude when $\phi_1 = \frac{\pi}{3}$ and $\phi_2 = \frac{7\pi}{3}$ .

19 Jan 2026

Answer :

Word Count : 245

The two collinear harmonic oscillations can be represented as: [ x_1 = a_1 \cos(\omega_0 t + \phi_1), \quad x_2 = a_2 \cos(\omega_0 t + \phi_2) ] The resultant displacement is: [ x = x_1 + x_2 = a_1 \cos(\omega_0 t + \phi_1) + a_2 \cos(\omega_0 t + \phi_2) ] ______ _____ ____ ________ _______ _______ _________ ______ __________ _________ _____.
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