Question

The interaction energy between two atoms is given by equation  where r is the inter-atomic separation. Show that for the particles to be in equilibrium, equation and show that in stable equilibrium the energy of attraction is seven times the energy of repulsion.

23 Jan 2025
Answer :
Word Count : 422
We are given the interaction energy between two atoms: \[ E(r) = -\frac{A}{r} + \frac{B}{r^7} \] where \( r \) is the inter-atomic separation, and \( A \) and \( B \) are constants. ### 1. To find the equilibrium distance \( r_e \), we need to minimize the total energy \( E(r) \). At equilibrium, the derivative of the potential energy \( E(r) \) with respect to \( r \) should be zero (since this corresponds to a minimum or maximum of the ______ ________ ____ _______ __________ _____ ____ __________ _______.
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