Question
Solve .
b) Write the ordinary differential equation
in the linear form, and hence find its solution.
c) Given that is one solution of the differential equation
find a second linearly independent solution of the equation.
Answer :
Word Count : 158
(a) [ \frac{dy}{dx}+xy=y^{2}e^{x^{2}/2}\sin x ] This is a Bernoulli equation. Divide by (y^{2}): [ y^{-2}\frac{dy}{dx}+x y^{-1}=e^{x^{2}/2}\sin x ] Let (v=y^{-1}). Then (\frac{dv}{dx}=-y^{-2}\frac{dy}{dx}). Hence [ -\frac{dv}{dx}+xv=e^{x^{2}/2}\sin x ] or [ \frac{dv}{dx}-xv=-e^{x^{2}/2}\sin x. _____ __________ ___ ____ _____ ____.
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(a) [ \frac{dy}{dx}+xy=y^{2}e^{x^{2}/2}\sin x ] This is a Bernoulli equation. Divide by (y^{2}): [ y^{-2}\frac{dy}{dx}+x y^{-1}=e^{x^{2}/2}\sin x ] Let (v=y^{-1}). Then (\frac{dv}{dx}=-y^{-2}\frac{dy}{dx}). Hence [ -\frac{dv}{dx}+xv=e^{x^{2}/2}\sin x ] or [ \frac{dv}{dx}-xv=-e^{x^{2}/2}\sin x. _____ __________ ___ ____ _____ ____.
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