Parenthesise the following C statement for its proper evaluation.

x + = a%b + c ∗ d/e ! = f + + − g

Further, if all the variables from a to g are initialised by 2, then what will be the value of x?

(((x += (((a % b) + ((c * d) / e))) != (f++ - g))))

Now, let's evaluate the expression step by step with all variables initialized to 2:

Given:
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