Parenthesise the following C statement for its proper evaluation.

x + = a%b + c ∗ d/e ! = f + + − g

Further, if all the variables from a to g are initialised by 2, then what will be the value of x?

(((x += (((a % b) + ((c * d) / e))) != (f++ - g))))

Now, let's evaluate the expression step by step with all variables initialized to 2:

Given:
a = ________ _________ ____ ___ ___ ______ ____ __________ ____ ___ _________.
___ ______ __________ ___ __________ _________ _________ _______ ______.
___ _____ _____ ________ _______ __________ _____ ________ ______.
_____ _____ ____ ________ _______ ______.
_________ _________ ___ ___ ____ _______ ________ ________ ______ _____ ____.
_______ ________ ___ ___ __________ _______ ________ ___ _______ ___.
_____ _____ ______ _____ ___ ______.
____ _____ ______ ___ _______ __________ __________ ___ ___.
____ _________ __________ _____ ______ ___ _________ _____ ________ _________ ____.
__________ _______ ____ _______ ___ ________ ____.
______ _________ ______ _______ ________ ______.
___ _____ ________ ______ _________ ___ ____ ___ ___ _________ ______.
________ ___ _______ _______ ____ ___ ___ _____.
_____ ____ __________ ____ ________ ____ _______ _______ _________.
_______ _______ _______ _____ ___ ___ ______ _________ ______ ________ _________ _______.
_______ _________ _________ ___ ____ _________ __________ ________ _____ _________ ____.
_________ __________ ___ ___ __________ ______ ______ _________ _______.
______ ______ _____ ______ _____ ___ ____ _______ ______ __________.
______.
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