Question
If y=em sin -1 X, then show that . Hence using Leibnitz’s formula, find the value of
.
Answer :
Word Count : 444
We are given the function \( y = e^m \sin^{-1}x \) and need to show that: \[ (1 - x^2) y_2 - x y_1 - m^2 y = 0 \] We also need to find the value of: \[ (1 - x^2) y_{n+2} - (2n + 1) x y_{n+1} \] ### Step 1: Derivatives of \( y = e^m \sin^{-1}x \) We start by finding the derivatives of \( y \). 1. First, differentiate _________ ____ _______ _________ ________ ___ ________ _______ _________ ________.
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We are given the function \( y = e^m \sin^{-1}x \) and need to show that: \[ (1 - x^2) y_2 - x y_1 - m^2 y = 0 \] We also need to find the value of: \[ (1 - x^2) y_{n+2} - (2n + 1) x y_{n+1} \] ### Step 1: Derivatives of \( y = e^m \sin^{-1}x \) We start by finding the derivatives of \( y \). 1. First, differentiate _________ ____ _______ _________ ________ ___ ________ _______ _________ ________.
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