Word Count : 262

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हमारे पास भिन्न है: $$ \frac{x-1}{x^3 - x^2 - 2x}. $$ सबसे पहले हर को गुणनखंडों में विभाजित करें। हर के हर को देखें: $$ x^3 - x^2 - 2x = x(x^2 - x - 2) = x(x-2)(x+1). $$ इसलिए हम लिख सकते हैं: $$ \frac{x-1}{x(x-2)(x+1)} = \frac{A}{x} + \frac{B}{x-2} + \frac{C}{x+1}. ________ ____ _________ __________ _____ ____.
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