Question

Find the direction cosines of the perpendicular from the origin to the plane


equation

09 Jan 2026
Answer :
Word Count : 151
The given plane equation is: [ \mathbf{r} \cdot (6\mathbf{i} + 4\mathbf{j} + 2\sqrt{3}\mathbf{k}) + 2 = 0 ] The vector normal to the plane is: _________ __________ ___ ___ _________ ___ ___.
_____ ____ __________ ____ _______ _________ ________ _________.
________ ____ __________ ___ ______ ________ ____ ___ ___ _____.
_________ ____ ________ __________ ______ ________ ______ __________ ___.
_________ ______ _________ _______ _______ ________ _____ _________ _________ _______ _______.
____ ____ ______ ________ _________ ___ _____ ___.
__________ _________ ____ _________ ____ _________ __________ __________.
____ ____ _______ _____ _____ ______ ________.
______ _______ ________ _____ _____ _________ _________ ___ _________ _____ _____.
__________ ___ __________ ______ ___ _______ ______ __________ ________ ____ _______ _________.
_________ ____ _________ ___ ______ ________.
___ ______ _________ ________ ________ ___ ______.
___ _______ ___ ______ __________ ____ _________ _______ __________ ______.
_________ ___ __________ ____ ________ ______ ________ ______ _____ _______ _________ __________.
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