Question
Calculate the Effective Atomic Number (EAN) of the Mn(CO)4NO complex. Here how is the
ligand NO treated as? In this was how the ligand NO becomes analogous to CO and N2?
Answer :
Word Count : 551
In the complex Mn(CO)₄NO, the Effective Atomic Number (EAN) is calculated by determining the number of electrons donated by the metal and its ligands. Manganese (Mn) has atomic number 25 and belongs to Group 7. Carbon monoxide (CO) is a neutral two-electron donor ligand, so four CO ligands donate a total of 8 electrons. The important point is the treatment of the nitrosyl (NO) ligand. Nitrosyl can coordinate to a metal in either a linear or bent manner. In Mn(CO)₄NO, NO is treated as a linear nitrosyl, NO⁺, and in electron-counting it behaves as a three-electron donor in the neutral/covalent method. Thus, the electron contribution is: Mn = 7 electrons 4CO = 4 × 2 = 8 electrons NO = 3 electrons Therefore, the total valence electron count is: 7 + 8 + 3 = 18 electrons. ________ _________ _____ ______ ____ __________ ________ ________ ___.
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In the complex Mn(CO)₄NO, the Effective Atomic Number (EAN) is calculated by determining the number of electrons donated by the metal and its ligands. Manganese (Mn) has atomic number 25 and belongs to Group 7. Carbon monoxide (CO) is a neutral two-electron donor ligand, so four CO ligands donate a total of 8 electrons. The important point is the treatment of the nitrosyl (NO) ligand. Nitrosyl can coordinate to a metal in either a linear or bent manner. In Mn(CO)₄NO, NO is treated as a linear nitrosyl, NO⁺, and in electron-counting it behaves as a three-electron donor in the neutral/covalent method. Thus, the electron contribution is: Mn = 7 electrons 4CO = 4 × 2 = 8 electrons NO = 3 electrons Therefore, the total valence electron count is: 7 + 8 + 3 = 18 electrons. ________ _________ _____ ______ ____ __________ ________ ________ ___.
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