Question
Write two-group criticality condition for a bare homogeneous reactor. Using this equation, show that the six factor criticality condition for two group theory is given by nf p pf pt =1.symbols have their usual meanings.
Answer :
Word Count : 355
To derive the six-factor criticality condition for a two-group theory from the two-group criticality equation for a bare homogeneous reactor, let's proceed step-by-step. ### Step 1: Two-Group Criticality Condition for a Bare Homogeneous Reactor The two-group criticality condition can be written as: \[ \frac{\Sigma_a^1}{\Sigma_f^1} \cdot \frac{1}{1 - \rho} = \frac{1}{\eta_1 \, \epsilon_1} \] Where: - \( \Sigma_a^1 \) is the absorption cross-section of group 1. - \( \Sigma_f^1 \) is the fission cross-section of group 1. - \( \rho \) is the reactivity. - \( \eta_1 \) is _____ __________ _____ _________ ________ ____ _____.
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To derive the six-factor criticality condition for a two-group theory from the two-group criticality equation for a bare homogeneous reactor, let's proceed step-by-step. ### Step 1: Two-Group Criticality Condition for a Bare Homogeneous Reactor The two-group criticality condition can be written as: \[ \frac{\Sigma_a^1}{\Sigma_f^1} \cdot \frac{1}{1 - \rho} = \frac{1}{\eta_1 \, \epsilon_1} \] Where: - \( \Sigma_a^1 \) is the absorption cross-section of group 1. - \( \Sigma_f^1 \) is the fission cross-section of group 1. - \( \rho \) is the reactivity. - \( \eta_1 \) is _____ __________ _____ _________ ________ ____ _____.
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