Question
Calculate the macroscopic scattering cross section for natural uranium. Given 3 18.9 g/cm , percentage weight of 235U in natural uranium is 0.713; the rest being 238U . The scattering cross sections for 235U and 238U isotopes being 15 b and 13.8 b, respectively.
Answer :
Word Count : 342
To calculate the macroscopic scattering cross-section (\(\Sigma_s\)) for natural uranium, we use the formula: \[ \Sigma_s = N \sigma_s \] where: - \( N \) is the number density of uranium atoms (\(\text{atoms/cm}^3\)), - \( \sigma_s \) is the microscopic scattering cross-section (\(\text{barns}\), where \( 1 \text{ b} = 10^{-24} \text{ cm}^2 \)). ### Step 1: Determine Number Density (\(N\)) The number density (\(N\)) is calculated as: \[ N = \frac{\rho N_A}{A} \] where: - \( \rho = 18.9 \, \text{g/cm}^3 \) (density of uranium), ___ ________ __________ _________ ______.
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To calculate the macroscopic scattering cross-section (\(\Sigma_s\)) for natural uranium, we use the formula: \[ \Sigma_s = N \sigma_s \] where: - \( N \) is the number density of uranium atoms (\(\text{atoms/cm}^3\)), - \( \sigma_s \) is the microscopic scattering cross-section (\(\text{barns}\), where \( 1 \text{ b} = 10^{-24} \text{ cm}^2 \)). ### Step 1: Determine Number Density (\(N\)) The number density (\(N\)) is calculated as: \[ N = \frac{\rho N_A}{A} \] where: - \( \rho = 18.9 \, \text{g/cm}^3 \) (density of uranium), ___ ________ __________ _________ ______.
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