Question
Write the expressions for two orthogonal plane polarised light waves propagating in z-direction and have equal amplitudes and phase difference of . Obtain the expression for the electric field of the resultant wave arising due to the superposition of these two waves. Determine the trajectory of the tip of the electric field vector associated with the resultant wave.
Answer :
Word Count : 341
We have two orthogonal plane-polarized light waves propagating in the \(z\)-direction with equal amplitudes and a phase difference of \(\delta\). Let’s write their mathematical expressions. ### Expressions for the Two Orthogonal Waves: 1. **Wave 1 (Polarized along the x-axis)**: \[ E_x = E_0 \cos(\omega t - k z) \] 2. **Wave 2 (Polarized along the y-axis) with phase difference \(\delta\)**: \[ E_y = E_0 \cos(\omega t - k z + \delta) \] ### Expression for the Resultant Electric Field: The resultant electric field is given _________ ________ ___ _____ ____ ______ _______ ______ ________ ______ _________ _____.
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We have two orthogonal plane-polarized light waves propagating in the \(z\)-direction with equal amplitudes and a phase difference of \(\delta\). Let’s write their mathematical expressions. ### Expressions for the Two Orthogonal Waves: 1. **Wave 1 (Polarized along the x-axis)**: \[ E_x = E_0 \cos(\omega t - k z) \] 2. **Wave 2 (Polarized along the y-axis) with phase difference \(\delta\)**: \[ E_y = E_0 \cos(\omega t - k z + \delta) \] ### Expression for the Resultant Electric Field: The resultant electric field is given _________ ________ ___ _____ ____ ______ _______ ______ ________ ______ _________ _____.
_______ _________ _______ ______ ____ ____ ______ ________ ________ _________ ____ _______.
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