Question
Write and run following programs using 8086 assembly language.
(a) Write and run an Assembly language program that converts a packed 4 digit BCD number that has been stored in two consecutive byte locations in the memory, into an equivalent binary number. The output should be stored in DX register. For example, if two consecutive byte locations have BCD values (12) and (34) then output will be binary equivalent of (1234)to which is (0000 0100 1101 0010)2. This binary value will be stored in DX register.
(b) Write and run (using appropriate calling program) a near procedure in 8086 assembly language that checks if the input parameter has a value less than 5. If the value is less than 5 then subroutines displays the line "Parameter value is less than 5" else it displays "Parameter value is >-5".
(c) Write and run an 8086 assembly language program that finds the factorial of the value stored in BH register. You may assume that BH register will store a maximum value 8. Thus, you need not handle the overflow.
Answer :
Word Count : 569
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We are solving manually, without Python, and we will write the 8086 assembly programs step by step for each part. I will show exact assembly logic, explain, and give the numerical conversion results where needed. --- ### (a) Convert 4-digit Packed BCD to Binary and Store in DX Example Input: Memory: ``` [2000H] = 12H ; high 2 BCD digits → 1 and 2 [2001H] = 34H ; low 2 BCD digits → 3 and 4 ``` Equivalent Decimal: 1234 Equivalent Binary: 0000 0100 1101 0010 (4D2H) Program: ```assembly ORG 1000H MOV SI, 2000H ; SI points to memory where BCD digits are stored MOV AL, [SI] ; AL = first byte (12H) MOV AH, AL ; Copy to AH for splitting AND AL, 0FH ; AL = lower nibble = 2 SHR AH, 4 ; AH = upper nibble = 1 __________ _____ __________ __________ ____ _________ ______ _____ __________ ____ ________.
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