Write and run a program using 8086 assembly language that increments a byte value stored in a memory location by a value 2. The result should be stored in the same memory location. For example, if a memory location contains 0101 0001, then the program will add 2 to this value and store the result 0101 0011 (after adding 2) in the same location
Sure, I can provide you with an example 8086 assembly language program that increments a byte value stored in a memory location by a value of 2 and stores the result back in the same memory location. Please note that you'll need an 8086 emulator or environment to run this program, such as DOSBox or an online assembler/emulator.
```assembly
ORG 100h ; Set origin address
MOV SI, 0000h ; Initialize source index to memory location
MOV AL, [SI] ; Load byte value from memory into AL register
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