Word Count : 146

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Let $A=\begin{pmatrix}2&1&1\\[2pt]1&3&2\\[2pt]1&0&0\end{pmatrix}$ and $B=\begin{pmatrix}1&2&3\\[2pt]0&1&4\\[2pt]5&6&0\end{pmatrix}$. Then $$ A+B=\begin{pmatrix}3&3&4\\[2pt]1&4&6\\[2pt]6&6&0\end{pmatrix}. $$ For matrix products, $$ AB=\begin{pmatrix} 7&11&10\\[2pt] 11&17&15\\[2pt] 1&2&3 \end{pmatrix},\qquad BA=\begin{pmatrix} 7&7&5\\[2pt] 5&3&2\\[2pt] 16&23&17 \end{pmatrix}. $$ Determinants are $\det(A)=-1$ and $\det(B)=1$, so both are invertible. Their inverses are $$ _______ ___ ___ ___ ______.
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