Question

Using molecular orbital method, construct all pssible trial wavefunctions (including spin) for a diatomic molecule. Of these functions, which trial function is expected to have the minimum energy? Give justification for your answer. 

19 Jan 2026
Answer :
Word Count : 1081
In the molecular orbital method, the electronic structure of a diatomic molecule is described by constructing molecular orbitals as linear combinations of atomic orbitals of the constituent atoms. For simplicity and clarity, consider a homonuclear diatomic molecule formed from two identical atoms A and B, each contributing one valence electron, so that the essential features of trial wavefunctions including spin can be illustrated without loss of generality. Let the relevant atomic orbitals be centered on nuclei A and B and denoted by ψA and ψB. The molecular orbitals obtained from these atomic orbitals are formed as symmetric and antisymmetric linear combinations, giving rise to bonding and antibonding orbitals respectively. The spatial molecular orbitals are written as ψ+ = N+(ψA + ψB) and ψ− = N−(ψA − ψB), where N+ and N− are normalization constants. The orbital ψ+ is symmetric with respect to interchange of the two nuclei and has increased electron density between the nuclei, corresponding to a bonding molecular orbital. The orbital ψ− is antisymmetric and has a nodal plane between the nuclei, corresponding to an antibonding molecular orbital. ___ _____ ____ _________ __________ __________ _________ ________ _____.
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