Question
The solution of the system of equations is attempted by the Gauss
Jacobi and Gauss Seidel iteration schemes. Set up the two schemes in matrix form. Will the iteration schemes converge? Justify your answer.
Answer :
Word Count : 526
We are given a linear system: $$ \begin{pmatrix}1 & 2\\ 2 & 1\end{pmatrix} \begin{pmatrix}x\\y\end{pmatrix} = \begin{pmatrix}4\\ -2\end{pmatrix} $$ That is, $$ \begin{aligned} x + 2y &= 4 \quad \text{(1)} \\ 2x + y &= -2 \quad \text{(2)} \end{aligned} $$ --- ### Step 1: Rewrite equations for iterative methods We rewrite each equation solving for the leading variable: From (1): $$ x = 4 - 2y \quad \text{(A)} $$ From (2): $$ y = -2 - 2x \quad \text{(B)} $$ --- ### Step 2: Jacobi Iteration Scheme In Jacobi, each new value is calculated using only values from the previous iteration. Using equations (A) and (B), the iterative formulas become: $$ \begin{aligned} x^{(k+1)} &= 4 - 2y^{(k)} \\ y^{(k+1)} &= -2 - 2x^{(k)} \end{aligned} $$ Or in matrix form: $$ \begin{pmatrix} x^{(k+1)} ______ _____ ____ _____ _________ _______ ____ _____ _____ _________ ____.
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We are given a linear system: $$ \begin{pmatrix}1 & 2\\ 2 & 1\end{pmatrix} \begin{pmatrix}x\\y\end{pmatrix} = \begin{pmatrix}4\\ -2\end{pmatrix} $$ That is, $$ \begin{aligned} x + 2y &= 4 \quad \text{(1)} \\ 2x + y &= -2 \quad \text{(2)} \end{aligned} $$ --- ### Step 1: Rewrite equations for iterative methods We rewrite each equation solving for the leading variable: From (1): $$ x = 4 - 2y \quad \text{(A)} $$ From (2): $$ y = -2 - 2x \quad \text{(B)} $$ --- ### Step 2: Jacobi Iteration Scheme In Jacobi, each new value is calculated using only values from the previous iteration. Using equations (A) and (B), the iterative formulas become: $$ \begin{aligned} x^{(k+1)} &= 4 - 2y^{(k)} \\ y^{(k+1)} &= -2 - 2x^{(k)} \end{aligned} $$ Or in matrix form: $$ \begin{pmatrix} x^{(k+1)} ______ _____ ____ _____ _________ _______ ____ _____ _____ _________ ____.
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