Word Count : 164

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The potential energy of the Neon crystal is given by: [ U(r) = -4 \varepsilon \left[ \left( \frac{\rho_0}{r} \right)^6 - \left( \frac{\rho_0}{r} \right)^{12} \right] ] where (\varepsilon = 3.12 \times 10^{-3}\ \text{eV}) and (\rho_0 = 2.82\ \text{Å}). For equilibrium, the potential __________ ___ ___ _____ ______ ___ ______ ___.
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