The following data is the data pertaining to a feeding trial on sheep. Treatments
A: Grazing only
B: Grazing + Maize Supplements
C: Grazing + Maize + Protein Supplement P1
D: Grazing + Maize + Protein Supplement P2
E: Grazing + Maize + Protein Supplement P3
Layout and Wool Yield (100 gm) is given as:
| 32(D) | 33(E) | 30(C) | 28(B) | 24(A) |
| 51(C) | 45(D) | 41(A) | 45(E) | 29(B) |
| 41 (E) | 29 (A) | 24 (B) | 36 (D) | 35 (C) |
| 38 (B) | 39(C) | 42(E) | 23(A) | 37(D) |
| 38(A) | 24(B) | 21(D) | 29(C) | 26(E) |
Analyse the design with appropriate method and calculate the Critical Difference for the treatment mean yield.
To analyze the feeding trial data and calculate the Critical Difference (CD) for the treatment mean yield, we can use analysis of variance (ANOVA) to determine if there are significant differences among the treatments. After conducting ANOVA, we can then calculate the CD to identify which treatment means are significantly different from each other.
Here are the steps to analyze the data:
Step 1: Organize the data:
Let's first organize the data into a table format for clarity:
| Treatment | Obs 1 | Obs 2 | Obs _____ _____ ____ ___ ______ ___ _______ _______ ____ _______ ___ ____. _______ _________ ________ _____ ________ ______ _____ _____. _______ __________ __________ ______ _____ ________ _____. _______ ____ _____ ____ _______ _________ ________ _____ _________ _______ _______. ______ _________ __________ ________ _______. ____ __________ ________ ___ ____ _________. _________ ______ _______ ______ ___ _____ _____. ________ ______ __________ ___ ________ ______ ________ ____ _____ ____ _________. _________ ________ ____ ____ __________ _______ _______ _______. ______ __________ ________ ________ _________ ____ ____ ___ ______. ______ _______ _______ ________ ____ ______ _____ _______ ___ _______ ____ ___. ______ ______ ______ _____ _____ ________. ____ _________ _________ _______ _______ __________ ____. __________ _________ ______ ________ _________ ______. _______ _____ ____ ________ ____ ______ ____ ________ _______ ________ ________. ____ __________ _____ ____ ___ __________. ______ _______ _____ __________ _________ __________ ____. ______ ______ ___ __________ ____ _________. _________ ____ ______ _______ __________. ________ _________ ________ __________ _____ ___ _________ ________ ___. ______ ____ __________ __________ __________ _____ ______ ________ __________ ________. _____ _____ ___ ________ ________ _________ _______ __________ _______ __________ _____ ______. ______ __________ ______ _____ ___ ____ ________ _________ _____ __________. _____ _______ ________ ______ ____. _______ ___ _______ _______ ____ ________ ______ __________ __________ __________. ____ ________ ______ _________ _____ _______ ____. _____ ___ _________ _________ ______. ____ ________ ____ __________ ______ _______ _________ ______ __________ ________ __________. ____ ______ ____ ___ _________ _____ _________ _________ __________ ________ _______. ________ _________ ______ _______ ______ _____. ________ ___ _______ _______ ____ ____ _____ ___. ______ ____ _________ _______ __________ _____ ______ _____ ________ _______. _________ _______ ______ ____ __________ _____. _____ ___ _________ ___ ___ ______ __________ ______ _____ _____. _________ __________ _________ _______ _____ ______ _______ _________ ________ _______ __________. _______ __________ _____ _________ ___ _____ ________ _______ _____ _________ _________ _____. _________ __________ ________ _______ ________ ______ ____ ____ ______ __________ _____ ________. ___ _________ ______ _________ ________. _________ _________ _______ _________ ____ __________ _________ ________ ____ ________ _________. _____ ______ ____ _______ ___ __________ ________ _____ ___ _____ ______. __________ ________ _______ _____ ___ ____ ________ __________ ___ _____ _________ _________. _______ ______ __________ _____ _____ _______ ______ ________ ____ _________ ___. _________ ______ ______ _____ ____ ______ ____ _______ ____. ________ ______ _______ __________ ________ _____ _________. _____ __________ ____ _______ ___ ________ ___ _________ _____ ____ ___ ____. _________ __________ ____ _____ _______ __________ ________ _____ _______ _______ _______ __________. ______ _____ _______ ______ _____ ___ _____ __________ _______ ___. ______ ______ ________ __________ ______ ________ ______ _______ ___ __________. ___ ______ _________ ____ ________ ____ ______ ______ _________ ____. ___ ______ ____. Get Full Answer on WhatsApp Related Questions A manurial trial with six levels of Farmyard Manure (FYM) was carried out in a randomised block design with 4 replications at the experimental station Junagarh with a new study the rate of decomposition of organic matters in soil and its synthetic capacity in soil on cotton crop. The yield per plot in kg for different levels of FYM and replications is given below: Cotton Yield Per Plot (in Kg)
A population consists of 10 villages with a total of 212 households. The second column of the accompanying table shows the number of households corresponding to each village. Select a PPS with replacement sample of 6 villages by using the Cumulative Total method:
A sample of 100 employees is to be drawn from a population of collages A and B. The population means and population mean squares of their monthly wages are given below:
In order to compare the mileage yields of 3 kinds of Gasoline, several tests were run, and the following results were obtained:
The following data is the data pertaining to a feeding trial on sheep. Treatments
In a population of size N = 5, the values of the population characteristics are 1, 3, 5, 7, 9, a sample of size 2 is drawn. Verify that y is an unbiased estimate of YandV(y) is equal to V(y)= In a class of Statistics, total number of students is 30. Select the linear and circular IGNOU NEWS Assignment Submission Last Date Extended Till 30 June 2026 Click Here★★★IGNOU June 2026 TEE Date Sheet Released Click Here★★★ Top |
|---|