Question

The failure data of 10 electronic components are shown in the table given below:

Failure Number 1 2 3 4 5 6 7 8 9 10
Operating Time (in hours) 3 5 31 51 76 116 140 182 250 302

Estimate, the
i) reliability. 
ii) cumulative failure distribution.
iii) failure density. 
iv) failure rate functions.

14 Feb 2023
Answer :
Word Count : 696

To estimate the reliability, we can use the following formula: R(t) = exp(-λt) where R(t) is the reliability at time t, and λ is the failure rate. To estimate λ, we can use the following formula: λ = (n - 1) / Σ(ti - ti-1) where n is the number of failures, ti is the operating time of the i-th failure, and ti-1 is the operating time of the (i-1)-th failure.

Using the given data, we can compute the values as follows:

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i ti ti-1 ti - ti-1 λ R(t)
1 3 0 3 0.003333 0.996675
2 5 3 2 0.003333 0.993362
3 31 5
What is the system reliability if R1 = R 3 = R 5 = R 7 = R 9 = 0.85 and
R 2 = R 4 = R 6 = R 8 = R10 = 0.95

The failure data of 10 electronic components are shown in the table given below:

Failure Number 1 2 3 4 5 6 7 8 9 10
Operating Time (in hours) 3 5 31 51 76 116 140 182 250 302

To monitor the manufacturing process of mobile phones, a quality controller randomly selected 100 mobile phones from the production line, each day over 15 days. The mobile phones were inspected for defectives and the number of defective mobile phones found each day was recorded. The data are given below:

Subgroup Number Number of Mobile Phones Inspected Number of Defective Mobile Phones
1 100 3
2 100 6
3 100 4
4 100 6
5 100 20
6 100 2
7 100 6
8 100 7
9 100 3
10 100 0
11 100 6
12 100 15
13 100 5
14 100 7
15 100 6

Solve the two-person zero-sum game having the following payoff matrix for player A

  Player B
B1 B2 B3 B4 B5
Player A A1 3 4 5 –2 3
A2 1 6 –3 3 7

State whether the following statements are True or False. Give reason in support of your answer. 
a) If the average number of defects in an item is 4, the upper control limit of the c-chart will be 12.
b) The specification limits and natural tolerance limits are same in statistical quality control.
c) If the probability of making a decision about acceptance or rejection of a lot on the first sample is 0.80 and the sizes of the first and second samples are 10 and 15, respectively, then
the average sample number for the double sampling plan will be 25.
d) Two independent components of a system are connected in series configuration. If the reliabilities of these components are 0.1 and 0.30, respectively then the reliability of the system will be 0.65.
e) A point in the pictorial representation of a decision tree having states of nature as immediate sub-branches is known as decision point. 

 

A shirt manufacturing company supplies shirts in lots of size 250 to the buyer. A single sampling plan with n = 20 and c = 1 is being used for the lot inspection. The company and the buyer decide that AQL = 0.04 and LTPD = 0.10. If there are 15  defective in each lot, compute the
i) probability of accepting the lot. 
ii) producer’s risk and consumer’s risk. 
iii) average outgoing quality (AOQ), if the rejected lots are screened and all defective shirts
are replaced by non-defectives. 
iv) average total inspection (ATI). 

A small electronic device is designed to emit a timing signal of 200 milliseconds (ms) duration. In the production of this device, 10 subgroups of four units are taken at periodic intervals and tested. The results are shown in the following table: 

Subgroup Number Duration of Automatic Signal (in ms)
a b c d
1 195 201 194 201
2 204 190 199 195
3 195 197 205 201
4 211 198 193 180
5 204 193 197 200
6 200 202 195 200
7 196 198 197 196
8 201 197 206 207
9 200 202 204 192
10 203 201 209 192
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