Question
Suppose the random variables X1 ,X2 and X3have the covariance matrix
Find all principal components.
Answer :
Word Count : 668
We are asked to find the principal components of a random vector $(X_1, X_2, X_3)$ with covariance matrix $$ \Sigma = \begin{bmatrix} 1 & -1 & 0 \\ -1 & 5 & 0 \\ 0 & 0 & 2 \end{bmatrix}. $$ Let’s solve this step by step, manually. --- ### Step 1: Find eigenvalues Principal components are obtained from the eigenvalues and eigenvectors of the covariance matrix $\Sigma$. The characteristic equation is: $$ \det(\Sigma - \lambda I) = 0. $$ So we compute: $$ \Sigma - \lambda I = \begin{bmatrix} 1-\lambda & -1 & 0 \\ -1 & 5-\lambda & 0 \\ 0 & 0 & 2-\lambda \end{bmatrix}. $$ The determinant is: $$ \det(\Sigma - \lambda I) = \begin{vmatrix} 1-\lambda & -1 & 0 \\ -1 & 5-\lambda & 0 \\ 0 & 0 & 2-\lambda \end{vmatrix}. $$ Since the matrix is block-diagonal in the 3rd variable, we can write: $$ \det(\Sigma - \lambda I) = (2 - \lambda) \cdot \det \begin{bmatrix} 1-\lambda & -1 \\ -1 __________ ____ ____ __________ ____ ______ ________ _________.
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We are asked to find the principal components of a random vector $(X_1, X_2, X_3)$ with covariance matrix $$ \Sigma = \begin{bmatrix} 1 & -1 & 0 \\ -1 & 5 & 0 \\ 0 & 0 & 2 \end{bmatrix}. $$ Let’s solve this step by step, manually. --- ### Step 1: Find eigenvalues Principal components are obtained from the eigenvalues and eigenvectors of the covariance matrix $\Sigma$. The characteristic equation is: $$ \det(\Sigma - \lambda I) = 0. $$ So we compute: $$ \Sigma - \lambda I = \begin{bmatrix} 1-\lambda & -1 & 0 \\ -1 & 5-\lambda & 0 \\ 0 & 0 & 2-\lambda \end{bmatrix}. $$ The determinant is: $$ \det(\Sigma - \lambda I) = \begin{vmatrix} 1-\lambda & -1 & 0 \\ -1 & 5-\lambda & 0 \\ 0 & 0 & 2-\lambda \end{vmatrix}. $$ Since the matrix is block-diagonal in the 3rd variable, we can write: $$ \det(\Sigma - \lambda I) = (2 - \lambda) \cdot \det \begin{bmatrix} 1-\lambda & -1 \\ -1 __________ ____ ____ __________ ____ ______ ________ _________.
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