Question
Let be a random vector with mean vector
and variance-covariance matrix
Find the means and covariance matrix for the linear combinations
or
in terms of and
Answer :
Word Count : 524
To solve this problem, we need to find the means and the covariance matrix for the linear combinations \( Z_1 = X_1 - X_2 \) and \( Z_2 = X_1 + X_2 \). ### 1. Mean Vector for \( Z \) The random vector \( Z = \begin{bmatrix} Z_1 \\ Z_2 \end{bmatrix} \) can be expressed as: \[ Z = C \cdot X = \begin{bmatrix} 1 & -1 \\ 1 & 1 \end{bmatrix} \begin{bmatrix} X_1 \\ X_2 \end{bmatrix} \] where \( C = \begin{bmatrix} 1 & -1 \\ 1 & 1 \end{bmatrix} \) is the transformation matrix. The mean of \( Z \) is calculated as: \[ \mu_Z = C \cdot \mu_X \] where \( \mu_X = \begin{bmatrix} \mu_1 \\ \mu_2 \end{bmatrix} \) is the mean vector of the random vector _____ __________ _____ ___ _____ __________ _____ ___.
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To solve this problem, we need to find the means and the covariance matrix for the linear combinations \( Z_1 = X_1 - X_2 \) and \( Z_2 = X_1 + X_2 \). ### 1. Mean Vector for \( Z \) The random vector \( Z = \begin{bmatrix} Z_1 \\ Z_2 \end{bmatrix} \) can be expressed as: \[ Z = C \cdot X = \begin{bmatrix} 1 & -1 \\ 1 & 1 \end{bmatrix} \begin{bmatrix} X_1 \\ X_2 \end{bmatrix} \] where \( C = \begin{bmatrix} 1 & -1 \\ 1 & 1 \end{bmatrix} \) is the transformation matrix. The mean of \( Z \) is calculated as: \[ \mu_Z = C \cdot \mu_X \] where \( \mu_X = \begin{bmatrix} \mu_1 \\ \mu_2 \end{bmatrix} \) is the mean vector of the random vector _____ __________ _____ ___ _____ __________ _____ ___.
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