Question

Suppose a large jar contains eight red balls, six yellow balls, and six blue balls. Two balls are to be selected at random from the jar, and the first ball selected will not be placed back into the jar.

01 Dec 2020
Answer :
Word Count : 564

To solve this problem, we can use principles of probability and combinatorics. We want to find the probability of certain events occurring when two balls are drawn without replacement from the jar containing eight red balls, six yellow balls, and six blue balls. Let's break down the problem step by step.

1. Total number of balls:
   In the jar, there are 8 red balls, 6 yellow balls, and 6 blue balls. So, the total number of balls in the jar is 8 + 6 + 6 = 20.

2. Probability of drawing a red ball on the first draw:
   Since there are 8 red balls in the jar and 20 total balls, the probability of drawing a red ball on the first draw is 8/20.

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