Starting from Lewis structures, determine the hybridisation type of the central atoms in  4 IF and ICI  4 .

To determine the hybridization type of the central atoms in \( \text{IF}_4^+ \) and \( \text{ICl}_4^- \), we first need to draw the Lewis structures for these molecules.

Lewis Structure of \( \text{IF}_4^+ \):
1. Iodine (\(I\)) has 7 valence electrons, and the molecule has a +1 charge, indicating the loss of one electron.
2. Fluorine (\(F\)) has 7 _________ ______ ________ ____ _____ ____ ____ ____ _________ ____ ______ _____.
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