Word Count : 586

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We are asked to solve the differential equation: [ (x^2y - 2xy^2)dx - (x^3 - 3x^2y)dy = 0. ] First, identify ( M(x, y) = x^2y - 2xy^2 ) and ( N(x, y) = -(x^3 - 3x^2y) = -x^3 + 3x^2y ). Check if the equation is exact: [ \frac{\partial M}{\partial y} = x^2 - 4xy, \quad \frac{\partial N}{\partial x} = -3x^2 + 6xy. ] Since (\frac{\partial M}{\partial y} \neq \frac{\partial N}{\partial x}), it is not exact. Look for an integrating factor. Notice that both (M) and (N) are homogeneous of degree 3. Try (y/x = v \Rightarrow y = vx, dy = vdx + xdv). Substitute (y = vx): [ Mdx - Ndy = [(x^2(vx) - ________ _________ ________ ______ ______ ____ ____ _____ __________ ________ __________.
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