Let be a random sample from a population with mean
and variance
. Consider the estimator
$
(i) Find the bias of the estimator .
(ii) Find the variance of .
(iii) Hence, calculate the Mean Square Error (MSE) of .
The estimator is given as: [ \hat{\mu} = \frac{1}{n} \sum_{i=1}^n X_i + 2 ] (i) Bias of (\hat{\mu}): By definition, bias is: [ \text{Bias}(\hat{\mu}) = E[\hat{\mu}] __________ __________ ________ __________ __________ ______ ____.
____ _________ ________ _____ _______ _______ ______ _____ ____ __________ ___.
___ ______ ________ _________ ________.
__________ ______ ____ ____ _______ _____ _________ ________ ____ ____ ______.
________ ____ _______ ____ ________ ___ ________.
________ _____ ______ ____ ___ _______ _______ _____ _____.
_________ _____ _____ ____ ____ ___ ______ __________ ____ _____ ________.
___ __________ ________ __________ ________ __________ _______ __________ ______ ____ __________ __________.
_____ _____ _______ ____ _______ ______ ______ ____ ___ ___ _____.
___ ___ __________ ______ _____ _________.
__________ __________ _____ _________ ____ ______ __________.
________ ___ _______ _____ ____.
_____ ____ _____.
Get Full Answer on WhatsApp
State whether the following statements are True or False. Give reasons in support of your answer:
(i) The mean square error is calculated when the estimator is unbiased.
(ii) If the sample size tends to infinity, the variance of a consistent estimator must tend to zero.
(iii) In the method of moments, population moments are equated to corresponding sample moments.
(iv) A 95% confidence interval is smaller than a 99% confidence interval.
(v) The chi-square distribution is symmetric for all degrees of freedom.
A survey was conducted to study the preference for online learning among students from urban and rural areas. Out of 300 urban students, 210 preferred online learning, while out of 250 rural students, 150 preferred online learning. Construct a 95% confidence interval for the difference between the population proportions of students preferring online learning in urban and rural areas.
Describe the following:
(i) t-distribution
(ii) General procedure of Testing of hypothesis
Let be a random sample from a population with mean
and variance
. Consider the estimator
$
(i) Find the bias of the estimator .
(ii) Find the variance of .
(iii) Hence, calculate the Mean Square Error (MSE) of .
Let X1, X2, ..., Xbe a random sample from the Exponential distribution with pdf f(x; 0) = 0e-ex, x > 0, 0 > 0
(i) Obtain the maximum likelihood estimator (MLE) of 0.
(ii) Hence, find the maximum likelihood estimate of for the observed sample: 2.1, 1.6, 3.4, 0.9, 2.5
A school caretaker looks after 6 children. The ages (in years) of the children are given below:
| Child | Age (in years) |
|---|---|
| Meena | 5 |
| Aarav | 4 |
| Nisha | 6 |
| Kabir | 4 |
| Pooja | 5 |
A researcher wants to compare the average test scores of students taught using Method A and Method B. A random sample of students was selected from each group, and their scores are given below:
| Student | Method A | Method B |
|---|---|---|
| 1 | 68 | 72 |
| 2 | 74 | 75 |
| 3 | 71 | 78 |
| 4 | 69 | 70 |
| 5 | 73 | 76 |
| 6 | 70 | 74 |
| 7 | 72 | 77 |
| 8 | 75 | 79 |