Question
Let ,
and
be partitioned as
,
and
. Then derive the conditional distribution of
.
Answer :
Word Count : 321
Let ( X \sim N_p(\mu, \Sigma) ) be partitioned as [ X = \begin{pmatrix} X^{(1)} \ X^{(2)} \end{pmatrix}, \quad \mu = \begin{pmatrix} \mu^{(1)} \ \mu^{(2)} \end{pmatrix}, \quad \Sigma = \begin{pmatrix} \Sigma_{11} & \Sigma_{12} \ \Sigma_{21} & \Sigma_{22} \end{pmatrix}, ] where ( X^{(1)} ) is ( k \times 1 ) and ( X^{(2)} ) is ( (p-k) \times 1 ). We want the conditional distribution _______ ________ _______ _______ _______ _____ _______ _____ ________ ____ ________.
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____ ________ ________ ________ _________ __________ ________ ______ _________.
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_______ _________ _____ ___ _____ ________ __________ ___ __________ __________.
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_______ _________ _________ ___ ________ ____.
_______ _____ __________ __________ ________.
___ _______ ________ _________ __________ ________ _____ _________ _____ ________ _________.
_____ _________ ______ _________.
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Let ( X \sim N_p(\mu, \Sigma) ) be partitioned as [ X = \begin{pmatrix} X^{(1)} \ X^{(2)} \end{pmatrix}, \quad \mu = \begin{pmatrix} \mu^{(1)} \ \mu^{(2)} \end{pmatrix}, \quad \Sigma = \begin{pmatrix} \Sigma_{11} & \Sigma_{12} \ \Sigma_{21} & \Sigma_{22} \end{pmatrix}, ] where ( X^{(1)} ) is ( k \times 1 ) and ( X^{(2)} ) is ( (p-k) \times 1 ). We want the conditional distribution _______ ________ _______ _______ _______ _____ _______ _____ ________ ____ ________.
___ _________ ____ _________ _________ _______ ______ ____ ____ ________ ____.
________ ____ ______ ________ __________ ________ _______.
___ ________ ______ ___ ________ _________.
____ ___ _______ _____ ________ ______.
____ _________ ______ ______ ________ __________ ___ ____ ___.
______ ________ _______ _____ _________ ______ _________ ______ _________.
______ _______ _______ ________ ________ ______ ________ ________ ___ _____ _________ ____.
________ ___ _______ ____ _____ _____ ______.
____ ________ ________ ________ _________ __________ ________ ______ _________.
_______ ___ _____ _____ ________ _____ ________ _____.
_______ ____ _____ ___ __________ _______ _____ ______ ____ ________ ____ ________.
_______ _________ _____ ___ _____ ________ __________ ___ __________ __________.
_____ ______ ___ ________ ___ __________ _____.
_______ ____ ______ ___ _________ ____ ______ _________ _________ __________.
_________ ________ ____ _____ _________.
___ ______ ______ _____ ____ __________ ___ _________ ______ _____ ___ ____.
_____ ______ ____ __________ ____ _______ _________ _________ _______ _________ _____ _________.
______ _______ __________ ___ ________ ______.
___ ______ ________ ___ ________ _________ ____ ______.
________ ___ ____ _____ _____.
______ ________ ___ __________ ______ _______ __________.
____ ______ __________ _______ _______ ______.
______ _______ __________ ______ ____.
__________ _____ __________ _________ ________ __________ ________ ________.
__________ ___ ______ _____ _________ _________ _________.
_________ _________ _____ ____ ___ _________ ___ _____ ________ __________.
__________ ____ ___ _______ _______ ________.
_______ _________ _________ ___ ________ ____.
_______ _____ __________ __________ ________.
___ _______ ________ _________ __________ ________ _____ _________ _____ ________ _________.
_____ _________ ______ _________.
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