Question
It is desired to estimate average annual wool yield per sheep for a herd of 150 at a certain farm house using stratified simple random sampling. Sheeps in the herd are to be grouped into three strata on the basis of first shaving in days. Optimum method sample allocation is said to be used for selecting the overall sample of 25 sheeps from the three strata. Determine approximately optimum strata boundaries using the information on first shaving given below.
| Shaving days | No. of Sheep (f ) |
| |||||||||||||||
| 30-70 | 6 | 2. 45 | |||||||||||||||
| 70-110 | 2 | 1.414 | |||||||||||||||
| 110-150 | 1 | 1 | |||||||||||||||
| 150-190 | 4 | 2 | |||||||||||||||
| 190-230 | 2 | 1.414 | |||||||||||||||
| 230-270 | 7 | 2. 646 | |||||||||||||||
| 270-310 | 8 | 2.828 | |||||||||||||||
| 310-350 | 20 | 4.472 | |||||||||||||||
| 350-390 | 10 | 3.162 | |||||||||||||||
| 390-430 | 25 | 5 | |||||||||||||||
| 430-470 | 40 | 6. 325 | |||||||||||||||
| 470-510 | 25 | 5 | |||||||||||||||
Answer :
Word Count : 318
Given the classwise values of $\sqrt{f}$: 30–70: 2.450 70–110: 1.414 110–150: 1.000 150–190: 2.000 190–230: 1.414 230–270: 2.646 270–310: 2.828 310–350: 4.472 350–390: 3.162 390–430: 5.000 430–470: 6.325 470–510: 5.000 Sum of all $\sqrt{f}$: 2.450 + 1.414 + 1.000 + 2.000 + 1.414 + 2.646 + 2.828 + 4.472 + 3.162 + 5.000 + 6.325 + 5.000 = 37.711 For 3 strata we ________ ______ ____ __________ ____ ______ _____ _____.
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Given the classwise values of $\sqrt{f}$: 30–70: 2.450 70–110: 1.414 110–150: 1.000 150–190: 2.000 190–230: 1.414 230–270: 2.646 270–310: 2.828 310–350: 4.472 350–390: 3.162 390–430: 5.000 430–470: 6.325 470–510: 5.000 Sum of all $\sqrt{f}$: 2.450 + 1.414 + 1.000 + 2.000 + 1.414 + 2.646 + 2.828 + 4.472 + 3.162 + 5.000 + 6.325 + 5.000 = 37.711 For 3 strata we ________ ______ ____ __________ ____ ______ _____ _____.
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