Word Count : 185

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The energy of incident photons is given by [ E = \frac{hc}{\lambda} ] Here, (h = 6.626 \times 10^{-34},\mathrm{Js}), (c = 3.00 \times 10^8,\mathrm{m/s}), and (\lambda = 180,\mathrm{nm} = 180 \times 10^{-9},\mathrm{m}). [ E = \frac{6.626 \times 10^{-34} \times 3.00 \times 10^8}{180 \times 10^{-9}} ] [ _____ _________ ______ ___ ________ ____ ________ _______ ___.
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