If the potential energy function is expressed as  calculate the inter-molecular distance at which the potential energy is a minimum. Show that in the stable configuration the energy of attraction is eight times the energy of repulsion.

To calculate the inter-molecular distance at which the potential energy is a minimum, let’s assume the potential energy function V(r)V(r) takes the form of a commonly used Lennard-Jones potential:

V(r)=Ar12−Br6V(r) = \frac{A}{r^{12}} - \frac{B}{r^6}

Here, AA and BB are constants, and rr is the inter-molecular distance. The first term represents the repulsive interaction (due to ______ __________ ____ _______ ________ _________ ______ ____.
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