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To find \(\frac{dy}{dx}\), you need to take the derivative of \(y\) with respect to \(x\). Given the expression for \(y\):

\[ y = \ln\frac{\sqrt{1+X}-\sqrt{1-X}}{\sqrt{1+X}+\sqrt{1-X}} \]

Let's define \(u\) as the numerator and \(v\) as the denominator:

\[ u = \sqrt{1+X}-\sqrt{1-X} \]
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