Word Count : 237

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To prepare 500 ml of 0.5 M Na₂CO₃, first calculate the required amount of solute. The molar mass of Na₂CO₃ is 106 g mol⁻¹. A 0.5 M solution means 0.5 moles per litre, so for 0.5 litres the number of moles required is 0.5 × 0.5 = 0.25 moles. The mass needed is therefore 0.25 × 106 = 26.5 ______ _____ ________ __________ ________ ___ _________.
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