Question

For a series of dependent trials the probability of success on any trial is  (k+1) / ( k+2) where k is equal to the number of successes on the previous two trials. Compute lim_{n\rightarrow \infty }P  [success on the n th trial].

07 Feb 2021
Answer :
Word Count : 275
We are tasked with solving the limit of the probability of success on the \(n\)-th trial in a sequence of dependent trials. The probability of success on any trial is given by: \[ P(\text{success on the n-th trial}) = \frac{k+1}{k+2} \] where \(k\) is the _____ _______ ___ ________ ________ _____ _____ ___ ___.
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