Question
For a common emitter transistor configuration if β = 120, IE = 5 mA, ro=∞ and R₁=2kΩ, calculate Zi, AV and Ai.
Answer :
Word Count : 290
To solve this numerically, we will use the following equations for a common emitter transistor configuration: ### Given Data: - Current gain, β = 120 - Emitter current, Iₑ = 5 mA = 5 × 10⁻³ A - Output resistance, r₀ = ∞ (ignored in calculations) - Base resistance, R₁ = 2 kΩ = 2000 Ω ### Step _______ _____ _____ ________ __________ ________ __________ _______.
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To solve this numerically, we will use the following equations for a common emitter transistor configuration: ### Given Data: - Current gain, β = 120 - Emitter current, Iₑ = 5 mA = 5 × 10⁻³ A - Output resistance, r₀ = ∞ (ignored in calculations) - Base resistance, R₁ = 2 kΩ = 2000 Ω ### Step _______ _____ _____ ________ __________ ________ __________ _______.
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