Word Count : 590

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Got it! Let’s carefully solve this manually, step by step. We’re dealing with a 4-bit Adder-Subtractor circuit. You said the operation is A − B, with: $$ A = 1010_2, \quad B = 1011_2 $$ --- ### Step 1: Understanding Adder-Subtractor A standard 4-bit adder-subtractor uses: * Full Adders (FA) for each bit. * C₀ (initial carry-in) = 0 for addition, and C₀ = 1 for subtraction (after XORing B with 1). * Subtraction is implemented as: $$ A - B = A + (\overline{B} + 1) $$ So, for subtraction, each B input to FA is XORed with 1, and initial carry $C_0 = 1$. --- ### Step 2: Prepare inputs for subtraction 1. A = 1010 → $A_3 A_2 A_1 A_0 = 1\,0\,1\,0$ 2. B = 1011 → $B_3 B_2 B_1 B_0 = 1\,0\,1\,1$ For subtraction: $$ B_i' = B_i \oplus 1 $$ So bitwise __________ _________ __________ _______ _____ __________ _______ _____ _______.
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