Question
Calculate the temperature at which the root mean square velocity of a chlorine molecule will be equal to its escape velocity from the earth’s gravitational field. Given that the radius of earth is 6400 km.
Answer :
Word Count : 211
हमें उस तापमान (\( T \)) की गणना करनी है, जहाँ क्लोरीन (\( Cl_2 \)) अणु का रूट मीन स्क्वेयर वेग (\( v_{rms} \)) पृथ्वी के पलायन वेग (\( v_{esc} \)) के बराबर हो जाए। ### दी गई जानकारी: - पृथ्वी का त्रिज्या, \( R = 6400 \) km = \( 6.4 _______ ________ __________ ______ ______ _________ _______.
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हमें उस तापमान (\( T \)) की गणना करनी है, जहाँ क्लोरीन (\( Cl_2 \)) अणु का रूट मीन स्क्वेयर वेग (\( v_{rms} \)) पृथ्वी के पलायन वेग (\( v_{esc} \)) के बराबर हो जाए। ### दी गई जानकारी: - पृथ्वी का त्रिज्या, \( R = 6400 \) km = \( 6.4 _______ ________ __________ ______ ______ _________ _______.
_________ ______ _______ ____ ___ ________ __________ ____ _______ ______ _____.
___ _______ _______ _______ _________ ____.
_______ ____ _____ _________ ____ ________ ________ ___.
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