Calculate the surface energy for a copper crystal for (110) plane. Copper has FCC structure with atomic radius 1.28 A. The heat of vaporization is 341 kJ mol.
To calculate the surface energy for a copper crystal on the (110) plane, we can use the following formula:
γ=12⋅ΔHvaporizationNA⋅A\gamma = \frac{1}{2} \cdot \frac{\Delta H_{\text{vaporization}}}{N_{\text{A}} \cdot A}
Where:
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γ\gamma is the surface energy (in J/m²),
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ΔHvaporization\Delta H_{\text{vaporization}} is the heat of vaporization per mole (in J/mol),
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NAN_{\text{A}} is Avogadro's number (6.022×10236.022 \times 10^{23} ________ _________ ___ ___ ______.
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