Calculate the standard internal energy change for the formation of water at 298 K. The standard enthalpy of formation of H₂O (l) at 298 K is-285.8 kJ mol^-1.

To calculate the standard internal energy change (ΔU°) for the formation of water, we use the relationship between enthalpy change (ΔH°) and internal energy change:

ΔH∘=ΔU∘+ΔnRT\Delta H^\circ = \Delta U^\circ + \Delta nRT

Here:

• ΔH∘=−285.8 kJ mol−1\Delta H^\circ = -285.8 \, \text{kJ mol}^{-1} (given),
• Δn=change in the number of moles of gas during the reaction\Delta n = \text{change _________ ______ _________ _______ _____ ___ ___ _________.
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