Question
Calculate the mean, and the variance of the following probability density functions:
i) Uniform
ii) Rayleigh distribution
Answer :
Word Count : 103
For the uniform density $p(x)=\frac{1}{2a}$ on $(-a,a)$ (zero elsewhere), symmetry gives $E[X]=\int_{-a}^{a}x\frac{1}{2a}\,dx=0$. Also $$ E[X^2]=\int_{-a}^{a}x^2\frac{1}{2a}\,dx=\frac{1}{2a}\cdot\frac{2a^3}{3}=\frac{a^2}{3}. $$ Hence $\operatorname{Var}(X)=E[X^2]-(E[X])^2=\frac{a^2}{3}$. For the _____ __________ ________ ____ _____ _________.
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For the uniform density $p(x)=\frac{1}{2a}$ on $(-a,a)$ (zero elsewhere), symmetry gives $E[X]=\int_{-a}^{a}x\frac{1}{2a}\,dx=0$. Also $$ E[X^2]=\int_{-a}^{a}x^2\frac{1}{2a}\,dx=\frac{1}{2a}\cdot\frac{2a^3}{3}=\frac{a^2}{3}. $$ Hence $\operatorname{Var}(X)=E[X^2]-(E[X])^2=\frac{a^2}{3}$. For the _____ __________ ________ ____ _____ _________.
_________ _____ ___ ____ ____ _________ ___ _________ ________.
_______ __________ _____ __________ _____ _________ ____ __________ ____ ____ _______ ____.
_______ _____ _______ ___ ______ __________ _______.
__________ ________ _______ _____ _______ ____ ____ ___ ________ _________ ________ __________.
_____ ________ __________ ________ ___ _________ ________ _______ ____ ________ _______.
________ ________ ________ ___ ______ ___ _____ ______ ____ ______ ________.
__________ _________ ____ ______ ____ _________.
_____ ____ _____ __________ __________ _________ ________ __________ _______.
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