Word Count : 461

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To solve this numerically, let’s go step by step. --- ### Step 1: Energy Loss in Neutron-Proton Scattering Since the neutron collides with hydrogen (a proton), we assume elastic scattering. The fraction of energy retained by the neutron in a single elastic collision with a stationary target of mass \( M \) is given by: \[ E' = E \cdot \left( \frac{(A-1)^2 + \cos^2\theta}{(A+1)^2} \right) \] where: - \( E \) is the initial neutron energy (2.6 MeV), - \( A \) is the atomic mass number of the target (for hydrogen, \( A = 1 \)), - \( \theta \) is the scattering angle in the LAB frame. For a neutron colliding with a ___ __________ ______ __________ ____ ____ __________ __________ ___ _____.
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