Question

b) Consider a particle undergoing simple harmonic motion. The velocity of the particle at position x_{1} is v_{1} and velocity of the particle at position x^{2} is v_{2}. Show that the ratio of time period (T) and amplitude (A) is:

\frac{T}{A}=2\pi\sqrt{\frac{x_2^{2}-x_{1}^{2}}{v_{2}^{1}x_{2}^{2}-v_{2}^{2}x_{1}^{2}}}

10 Mar 2024
Answer :
Word Count : 350
To show the ratio of the time period (T) to the amplitude (A) for a particle undergoing simple harmonic motion (SHM) based on the given conditions, we can start with the equation for velocity in SHM. ### Step 1: Equation of motion for simple harmonic motion (SHM) In SHM, the total mechanical energy is conserved. The energy at any point is the sum of kinetic energy and potential energy, and ______ ___ ________ ________ _________ ___ ___ __________ _______ ____ ________.
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