Word Count : 125

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Short answer: Not planar. Proof (manual): Let $C_5=\{a_1,a_2,a_3,a_4,a_5\}$ and let $K_5=\{b_1,b_2,b_3,b_4,b_5\}$. Vertices of the Cartesian product $C_5\times K_5$ are pairs ___ _____ _________ _____ __________ _____ ______ _______ __________ __________ ________.
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