Question
Assume that in a population each person is equally likely to have a particular disease and disease status of each individual is independent of each other, then find the probability that out of the 5 randomly selected individuals who are tested for this particular disease exactly 3 have this disease.
Answer :
Word Count : 263
To find the probability that out of 5 randomly selected individuals, exactly 3 have a particular disease, we can use the binomial probability formula. The binomial probability formula is given by: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] where: - \( n \) is the total number of trials (in this case, 5 individuals), - \( k \) is the number of successes __________ ______ ____ _____ ________ ______ _______ ______.
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To find the probability that out of 5 randomly selected individuals, exactly 3 have a particular disease, we can use the binomial probability formula. The binomial probability formula is given by: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] where: - \( n \) is the total number of trials (in this case, 5 individuals), - \( k \) is the number of successes __________ ______ ____ _____ ________ ______ _______ ______.
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