Question

An irregular six faced die is thrown and the expectation that in 10 throws it will give five even numbers is twice the expectation that it will give four even numbers. How many times in 10,000 sets of 10 throws would you expect it to give no even number?

25 Nov 2020
Answer :
Word Count : 273

To solve this problem, we can use the concept of probability and expectation in numerical and statistical computing. 

Let's denote the probability of getting an even number on a single throw as "p" and the probability of getting an odd number as "q." Since there are 6 faces on the die, the sum of these probabilities should be 1, so p + q = 1. Given that the ___ ________ __________ ______ __________ _____ _______.
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