Question

a) Suppose two friends Anjali and Prabhat trying to meet for a date to have lunch say between 1 pm to 2 pm. Suppose they follow the following rules for this meeting:
Each of them will arrive either on time or 10 minutes late or 20 minutes late or 30 minutes late or 40 minutes late or 50 minutes late or 1 hour late. All these arrival times are equally likely for both of them.
Whoever of them reaches first will wait for the other to meet only for 10 minutes. If within 10 minutes the other does not reach, he/she leaves the place and they will not meet.
Find the probability of their meeting.

24 Mar 2026
Answer :
Word Count : 638
The situation can be modeled using the framework of discrete probability distributions where both individuals independently choose their arrival times from a finite set of equally likely outcomes. Let us define the possible arrival times in minutes after 1 pm as 0, 10, 20, 30, 40, 50, and 60. Thus, each of them has 7 possible choices, and since all these choices are equally likely, the probability of each arrival time is ( \frac{1}{7} ). Because the arrival times of Anjali and Prabhat are independent, the combined sample space consists of all ordered pairs of these times, giving a total of ( 7 \times 7 = 49 ) equally likely outcomes. To determine whether they meet, we must interpret the rule carefully: whoever arrives first waits for the other person for only 10 minutes. If the other person does not arrive within that 10-minute window, the first person leaves, and the meeting does not occur. Therefore, they will meet ______ ___ _____ ____ _____ ___ ___ ________ ____ ___ _______.
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